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Hcf(420,130)=10,find LCM |
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Answer» Rule:LCM * HCF = x * yProduct of two numbers = product of given numbers LCM = (420*130)/10 = 5460 Prime factorisation of 420 = 2 × 2 × 3 × 5 × 7Prime factorisation of 130 = 2 × 5 × 13HCF of 420 and 130 = 2 × 5 = 10LCM ×\xa0HCF = Product of the Numbers10 × LCM = 420 × 130LCM = 420 × 13 = 5460 7800 |
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