Saved Bookmarks
| 1. |
HCF and LCM of 404 and 96 and verify that HCF ×LCM = product of two no |
| Answer» Prime factorisation of 404 and 96 is:404 = 2\xa0{tex}\\times{/tex}\xa02\xa0{tex}\\times{/tex}\xa0101404 = 22\xa0{tex}\\times{/tex}\xa010196 = 2\xa0{tex}\\times{/tex}\xa02\xa0{tex}\\times{/tex}\xa02\xa0{tex}\\times{/tex}\xa02\xa0{tex}\\times{/tex}\xa02\xa0{tex}\\times{/tex}\xa0396 = 25\xa0{tex}\\times{/tex}\xa03{tex}\\therefore{/tex}\xa0HCF(404,96 )= 22 = 4LCM(404, 96 ) = 101\xa0{tex}\\times{/tex}\xa025\xa0{tex}\\times{/tex}\xa03LCM( 404, 96) = 9696now we have to verify that,HCF(404, 96)\xa0{tex}\\times{/tex}LCM(404, 96) = 404{tex}\\times{/tex}96Hence,LHS = HCF\xa0{tex}\\times{/tex}\xa0LCM = 4\xa0{tex}\\times{/tex}\xa09696 = 38784\xa0RHS= Product of numbers =404\xa0{tex}\\times{/tex}\xa096 = 38784Since, LHS=RHSi.e. HCF\xa0{tex}\\times{/tex}\xa0LCM = Product of 404 and 96.hence verified | |