HCF of 867 and 255

1.	HCF of 867 and 255
Answer» By using Euclid division Lemmaa=bq+rwhere a is > bso a = 867 and b =255867=255×3+102here r≠ 0 so a = 255 and b = 102255 = 102 × 2 + 51here r ≠ 0 so a = 102 and b = 51102 = 51 × 2 + 0here r = 0so, Hcf of (867,255) is = 51

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