1.

How does refractive index (μ) of a material vary with respect to wavelength (λ). (A and B are constants).(a) μ = A + \(\frac{B}{λ^2}\) (b) μ = A + Bλ2(c) μ = A +\(\frac{B}{λ}\) (d) μ = A + Bλ

Answer»

(a) μ = A + \(\frac{B}{λ^2}\) 

According to cauchy’s relation, (a) μ = A + \(\frac{B}{λ^2}\) 



Discussion

No Comment Found

Related InterviewSolutions