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How does refractive index (μ) of a material vary with respect to wavelength (λ). (A and B are constants).(a) μ = A + \(\frac{B}{λ^2}\) (b) μ = A + Bλ2(c) μ = A +\(\frac{B}{λ}\) (d) μ = A + Bλ |
Answer» (a) μ = A + \(\frac{B}{λ^2}\) According to cauchy’s relation, (a) μ = A + \(\frac{B}{λ^2}\) |
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