How many 176 ohm resistors (in parallel) are required to carry 5 A on

1.	How many 176 ohm resistors (in parallel) are required to carry 5 A on a 220 V line?
Answer» For x number of resistors of resistance 176 Ω,Here Supply voltage, V = 220 VCurrent, I = 5 AEquivalent resistance of the combination = R, given as1÷R=x × [1÷176]R=176÷xfrom Ohm\'s lawV÷I = 176÷xx={176×I} ÷ Vx={176×5} ÷ 220x=4∴four resistors of 176 Ω are required to draw the given amount of current.

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