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How many 76ohm resistors are required to carry 5A in 220 unit. |
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Answer» You\'re welcome Thanks Have u got it... Let n resistor be connected in parallel, then equivalent resistance = 1/R = 1/R1+ 1/R2+........+(n times) => 1/R = 1/176+1/176 +.........+(n times) => 1/R = n×1/176 => 1/R = n/176.......(1) . From ohm\'s law, R=V/I = 220/ 5 = 44 ohm......(2) . Now, put the value of (2) in (1) , we get, 1/44= n/176 => n = 176/44 => n = 4. How? 4 resistor |
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