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How many address bits are needed to operate a 2K * 8-bit memory?(a) 10(b) 11(c) 12(d) 13I got this question in an interview for job.My question is based upon Programmable Read Only Memory in chapter Memory Devices of Digital Circuits

Answer»

Correct answer is (b) 11

To EXPLAIN I would say: For N address bits, the memory LOCATION will consist of 2^n bits. Thus, for 2K, only 11 address bits are required, because 2^11 = 2K.



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