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How many address bits are required to select memory location in the Memory decoder?(a) 4 KB(b) 8 KB(c) 12 KB(d) 16 KBThis question was posed to me during an online interview.My question is taken from Programmable Logic Array in division Memory Devices of Digital Circuits

Answer»

Correct OPTION is (c) 12 KB

To elaborate: Memory decoder decodes the memory to be SELECTED for a specific address. Since the given EPROM and RAM are of 4 KB (4 * 1024 = 4096) CAPACITY, it requires 12 address bit to select one of the 4096 memory locations.



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