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How many gallons of each of a 4% and an 11% acid solutions should be mixed to obtain 35 gallons of a 7% solution?1). 20 gallons, 15 gallons2). 22 gallons, 13 gallons3). 13 gallons, 22 gallons4). 15 gallons, 20 gallons |
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Answer» Let US denote by y gallons the AMOUNT of 4% solution. ⇒ The amount of solution of 11% acid solution = 35 - y gallons
SOLVING 0.07 (35) = 0.04y + 0.11 (35 - y),we get y = 20 gallons If y = 20 gallons; then the other amount, denoted by 35 - y must be 35 - 20 = 15 gallons. |
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