1.

How many memory locations are addressed using 18 address bits?(a) 165,667(b) 245,784(c) 262,144(d) 212,342This question was addressed to me during an interview.This is a very interesting question from Programmable Read Only Memory in portion Memory Devices of Digital Circuits

Answer»

The correct choice is (C) 262,144

Explanation: For N ADDRESS BITS, the memory location will consist of 2^n bits. USING 18 address bits, 2^18 = 262,144 (= 256 K) words are addressed.



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