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How many multiples of the number 213 × 35 × 53 × 76 are perfect cubes or complete cubes?1. 242. 603. 364. 48 |
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Answer» Correct Answer - Option 2 : 60 The given number is: 213 × 35 × 53 × 76 For each term, the perfect cubes can be obtained as: For 213 = 20, 23, 26, 29, 212; i.e. 5 terms For 35 = 30, 33; i.e. 2 terms For 53 = 50, 53; i.e. 2 terms For 76 = 70, 73, 76; i.e. 3 terms So, we have the multiples of the number 213 × 35 × 53 × 76 as perfect cubes = 5 × 2 × 2 × 3 = 60 ∴ The number of multiples of the number 213 × 35 × 53 × 76 are perfect cubes or complete cubes, are 60 |
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