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How many terms are there in the AP 41,38,35,...,8?

Answer» An= a + (n-1)dwhere, a= 41 and d = a2 -a1=38-41=-3now, 8 = 41 + (n-1)-38-41=-3n+3-33 = -3n+3-33-3 =-3n-36=-3nn =12Answer: 12 terms.
An= a + (n-1)dwhere, a= 41 and d = a2 -a1=38-41=-3now, 8 = 41 + (n-1)-38-41=-3n+3-33 = -3n+3-33-3 =-3n-36=-3nn =12therefore there are 12 terms.


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