How many terms of an AP 34,43,52,61, .......Must be taken so that there sum is equal to 1002

How many terms of an AP 34,43,52,61, .......Must be taken so that ther

1.	How many terms of an AP 34,43,52,61, .......Must be taken so that there sum is equal to 1002
Answer» Sn= n/2[2à+(n-1)d]1002=n/2[234+(n-1)9]10022= n[68+9n-9]2004= n[59+9n]2004= 59n+9n^2 Use sum of ap formula,