InterviewSolution
Saved Bookmarks
| 1. |
How many terms of the sequence 18,16,14........ should be taken so that their sum is zero |
|
Answer» We know that\xa0sum = n/2(2a + (n-1) d) 0 = n/2(2 * 18 + (n - 1) * (-2)) 0 = n/2(36-2n+2) 0 = 38n - 2n^2 2n^2 - 38n = 0 2n(n-19) = 0 n - 19 = 0 n = 19. Ans is 19 term 19 |
|