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                                    How many three digit number divisible by 7? | 
                            
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Answer» here a= 105l= 994n=?d= 7so994 = 105+(n-1) 7= 105+7n-7994= 98+7n994-98 = 7n896/7 = nn= 128so 128 three digit numbers are divisible by 7 Given,A(first term)=105,An(last term)=994,d( common difference)=7,n=?An=A+(n-1)d995=105+(n-1)7887=(n-1)7n-1=127n=127+1=128Hence, there are total 128 three digit no. divisible by 7.  | 
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