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how many three of digit natural numbers are divisible by 7

Answer» 105, 112, 119, ..., 994This is an AP with first term (a) = 105 and common difference (d) = 7Let an be the last term.an = a + (n - 1)d994 = 105 + (n - 1)(7)7(n - 1) = 889n - 1 = 127n = 128Thus, there are 128 three-digit natural numbers that are divisible by
Three digit numbers divisible by 7 are
105, 112, 119, ..., 994This is an AP with first term (a) = 105 and common difference (d) = 7Let an\xa0be the last term.an\xa0= a + (n - 1)d994 = 105 + (n - 1)(7)7(n - 1) = 889n - 1 = 127n = 128Thus, there are 128 three-digit natural numbers that are divisible by 7.


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