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How many times will the intensity of a narrow `X`-ray beam of wavelength `20pm` decrease after passing through a lead plate of thickness `d = 1.0 mm` if the mass absorption coefficient for the given radiation wavelength is equal to `mu//rho = 3.6 cm^(2)//g`? |
Answer» The transmission factor is `e^(-mu d)` and so the intensity will decrease `e^(mu d)` `=e^(3.6 xx 11.3 xx 0.1) = 58.4` timestimes (we have used `mu = (mu//rho) xx rho` and used the known value of density of lead). |
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