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How to prove ✓7 irrational |
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Answer» let us assume that √7 be rational.then it must in the form of p / q [q ≠ 0] [p and q are co-prime]√7 = p / q=> √7 x q = psquaring on both sides=> 7q2= p2\xa0 ------> (1)p2 is divisible by 7p is divisible by 7p = 7c [c is a positive integer] [squaring on both sides ]p2 = 49 c2 --------- > (2)substitute p2 in equ (1) we get7q2 = 49 c2q2 = 7c2=> q is divisible by 7thus q and p have a common factor 7.there is a contradiction as our assumption p & q are co prime but it has a common factor.so that √7 is an irrational. Ok last mai then root 7p be rational then irrational And last write hence prove Root 7 =p/q where is not equal to 0 Let root 7 be a rational no in the form p/q Ok To Pura bata do adha answer kyon bata rage ho Let root 7 be irrational |
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