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`" if " |{:(1,,1,,1),(a,,b,,c),(bc,,ca,,ab):}|=|{:(1,,1,,1),(a,,b,,c),(a^(3),,b^(3),,c^(3)):}|` where a,b,c are distinct positive reals then the possible values of abc is`//`areA. `(1)/(18)`B. `(1)/(63)`C. `(1)/(27)`D. `(1)/(18)`

Answer» Correct Answer - A::B
we have
`(a-b)(b-c)(c-a)=(a-b)(b-c)(c-a)(a+b+c)`
`rArr a+b+c =1`
As a , b, and c are positive
using `AM gt GM` we get
`(a+b+c)/(3) gt (abc)^(1/3)`
`:. Abc lt (1)/(27)`


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