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If 1/2 is a root of the equation x^2+kx-5/4=0, then find the value of k.

Answer» p(x)=x^2+kx-5/4=0If x=1/2Then p(1/2)= (1/2)^2+k(1/2)-5/4=0 p(1/2)= 1/4+k/2 -5/4=0 => -4/4+k/2=0 => k/2 -1=0 => k/2 =1 => k=2........ans.


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