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If 1 - a2 = a, then what is the value of \(a^6+\frac{1}{a^6}\) ?1. -162. +163. -184. +18 |
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Answer» Correct Answer - Option 4 : +18 Given: 1 - a2 = a Calculation: As, 1 - a2 = a Dividing the given equation by 'a', we get \( {1 \ \over a}\)- a = 1 ----(i) Cubing equation (i), we get \( {1 \ \over a^3}\) - a3 - 3 × \( {1 \ \over a}\)× a × (\( {1 \ \over a}\)- a) = 1 \( {1 \ \over a^3}\) - a3 = 1 + 3 = 4 ----(ii) squaring equation (ii), we get \({1 \ \over a^6}\) + a6 - 2 = 16 \({1 \ \over a^6}\) + a6 = 16 + 2 = 18 ∴ The value of \({1 \ \over a^6}\) + a6 is 18 |
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