1.

If 1 - a2 = a, then what is the value of \(a^6+\frac{1}{a^6}\) ?1. -162. +163. -184. +18

Answer» Correct Answer - Option 4 : +18

Given:

1 - a2 = a

Calculation:

As, 1 - a2 = a

Dividing the given equation by 'a', we get

\( {1 \ \over a}\)- a = 1      ----(i)

Cubing equation (i), we get

\( {1 \ \over a^3}\) - a3 - 3 × \( {1 \ \over a}\)× a × (\( {1 \ \over a}\)- a) = 1

\( {1 \ \over a^3}\) - a3  = 1 + 3 = 4     ----(ii)

squaring equation (ii), we get

\({1 \ \over a^6}\) + a6 - 2 = 16

\({1 \ \over a^6}\) + a6 = 16 + 2 = 18

∴ The value of \({1 \ \over a^6}\) + a6 is 18



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