If 1 and -2 are two zeros of the polynomial(x^3-4x^2-7x+10), finds its

1.	If 1 and -2 are two zeros of the polynomial(x^3-4x^2-7x+10), finds its third zero
Answer» Given zeroes are- 1, -2Or, (x-1) and (x+2).(x-1)(x+2)=x^2+x-2If we divide x^3-4x^2-7x+10 by x^2+x-2 we get x-5, i.e., required answer

Discussion