If 1+sin^2theta=3sintheta*costheta then prove that tantheta=1 or 1/2

1.	If 1+sin^2theta=3sintheta*costheta then prove that tantheta=1 or 1/2
Answer» 1+sin^2 theta=3 sin\xa0theta cos theta (we know that sin^2 theta + cos^2 theta =1)= ( sin^2 theta + cos^2 theta ) + sin ^2 theta = 3 sin theta cos theta= sin^2 theta + cos^2 theta + sin ^2 theta = 3 sin theta cos theta= cos^2 theta + 2 sin^2 theta = 3 sin theta cos thetaOn dividing by cos^2 theta, we get= 1 + 2 tan^2 theta = 3 tan thetaLet tan theta = b\xa02b^2 - 3b + 1 = 0= (2b-1)(b-1) = 0b = 1 or 1/2So, tan theta = 1 or 1/2.\xa0

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