Saved Bookmarks
| 1. |
If (1²+2²+3²+4²...........+12²)=650 then what is the value of X in (2²+4²+6²+8².........+24²)=X. |
|
Answer» (2^2 + 4^2 + 6^2 + ........+24^2 ) = x => 2^2 ( 1^2 + 2^2 + 3^2 +......12^2) = x => 4×650 =>2600 How x = 2,600. |
|