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If 2 and -3 are the zeroes of the quadric polynomial x^2+(a+1)x+b then values of a and b |
| Answer» Putting 2 as p(2) as 2 is a zero of this quadratic polynomial.we get 2a +b = -6 as first equation. Put -3 as p(-3) as -3 is another zero of this quadratic polynomial.we get 3a - b = 6 as second equation. Adding these equations we get a= 0 and after that put a in first we get b= -6 | |