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If 2 is a root of x^2+bx+q=0 has equal roots the. find q |
| Answer» x2 + bx +12=0.2 is a root of the equation.Then, 4+2b+12=0.Then, 2b+16=0.So, 2b=\xa0-16.Therefore, b= -8.x2+bx+q=0.x2-8k+q=0.Equal roots, so b2 =4ac.64=4 × 1×qq=16. | |