1.

If 2 sin2 x = 3 cos x, where 0 ≤ x ≤ 2 π, then find the value of x.

Answer»

2sin2x = 3cos x 

2 - 2cos2x = 3cos x 

Solving the quadratic equation, we get 

cos x = \(\frac{1}2\)

Therefore x = 60° and 300° 

i.e.

θ  = \(\frac{π}3\) and \(\frac{5π}3\)



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