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If 2 sin2 x = 3 cos x, where 0 ≤ x ≤ 2 π, then find the value of x. |
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Answer» 2sin2x = 3cos x 2 - 2cos2x = 3cos x Solving the quadratic equation, we get cos x = \(\frac{1}2\) Therefore x = 60° and 300° i.e. θ = \(\frac{π}3\) and \(\frac{5π}3\) |
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