1.

If `2sin^(2)theta-cos^(2)theta=2`, then find the value of `theta`.

Answer» `2sin^(2)theta=cos^(2)theta=2`
`rArr2sin^(2)theta-(1-sin^(2)theta)=2`
`rArr2sin^(2)theta-1+sin^(2)theta=2`
`rArr3sin^(2)theta=3rArrsin^(2)theta=1`
`rArrsin theta=1rArrtheta=90^(@)`


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