InterviewSolution
Saved Bookmarks
| 1. |
If `2sin^(2)theta-cos^(2)theta=2`, then find the value of `theta`. |
|
Answer» `2sin^(2)theta=cos^(2)theta=2` `rArr2sin^(2)theta-(1-sin^(2)theta)=2` `rArr2sin^(2)theta-1+sin^(2)theta=2` `rArr3sin^(2)theta=3rArrsin^(2)theta=1` `rArrsin theta=1rArrtheta=90^(@)` |
|