If 2sin(3x-15)°=√3 then find the value of sin^2(2x+10)°+tan(x+5)°

1.	If 2sin(3x-15)°=√3 then find the value of sin^2(2x+10)°+tan(x+5)°
Answer» Sin(3x-15)=√3/2Sin(3x-15)=sin 60 3x-15=60 3x=60+15 3x=75 x=15Sin^2(215+10)Sin^2(45)Sin45sin451

Discussion