1.

If 2x+3y=34 and ((x + y)/y)=13/8,then find the value of 5y+7x.

Answer»

The given equations are: 

2x+3y=34 …(i) and, 

((x + y) /y)=13/8 

8x+8y=13y 

8x-5y=0 …(ii) 

Multiplying (i) by 5,(ii) by 3 and adding, we get : 

34x=170 or x=5. 

Putting x=5 in (i), we get: y=8. 

5y+7x=((5*8)+(7*5))=40+35=75



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