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| 1. |
If 2x,x+10,3x+2 are in A.P find the value of x. |
| Answer» Since 2x,x+10 and 3x+2 are in APTherefore the common difference must be same.So x+10-2x=3x+2-(x+10) -x+10=3x+2-x-10 -x+10=2x-8 -x+10-2x+8=0 -3x+18=0 -3x=-18 x={tex}-18\\over -3{/tex} x=6\xa0 | |