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If 3(5x - 7) - 4(8x - 13) = 2 (9x - 11) - 17, then the value of \(\frac{7x -5}{11x-9}\) is1. \(\frac{9}{13}\)2. \(\frac{14}{31}\)3. \(-\frac{14}{31}\)4. \(-\frac{14}{13}\) |
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Answer» Correct Answer - Option 1 : \(\frac{9}{13}\) 3(5x - 7) - 4(8x - 13) = 2 (9x - 11) - 17 Calculations: 3(5x - 7) - 4(8x - 13) = 2 (9x - 11) - 17 ⇒ 15x - 21 - 32x + 52 = 18x - 22 - 17 ⇒ -17x + 31 = 18x - 39 ⇒ 18x + 17x = 31 + 39 ⇒ 35x = 70 ⇒ x = 70/35 ⇒ x = 2 \(\frac{7x -5}{11x-9}\) = \(\frac{{7×2 -5}}{{11× 2}-9}\) ⇒ (14 - 5) ÷ (22 - 9) ⇒ 9/13 ∴ The required value is 9/13 |
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