If -3 is one of the zeroes of the polynomial (k-1)x^2+kx+1, find the v

1.	If -3 is one of the zeroes of the polynomial (k-1)x^2+kx+1, find the value of k .
Answer» p(x) = (k-1)x2\xa0+ kx + 1Since, -3 is a zero of the polynomial.p(-3) = (k - 1)(-3)2\xa0+ k(-3) + 1 = 09(k - 1) - 3k + 1 = 09k - 9 - 3k + 1 = 06k - 8 = 06k = 8k = 8/6k = 4/3

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