If 3 tanA = 4 find the value of (5 sinA - 3 cosA)/ (5 sinA + 2 cosA)

1.	If 3 tanA = 4 find the value of (5 sinA - 3 cosA)/ (5 sinA + 2 cosA)
Answer» given: 3tanA = 4 tan A = 4/3 P/B = 4/3 BC/AB = 4/3 (LET A TRIANGLE RIGHT ANGLED AT B BASE AB AND PERPENDICULAR BC AND HYPOTENUSE AC.) BC = 4K AND AB =3KUSING PYTHAGORAS THEOEMAC = 5KSIN A = 4/5COS A = 3/5NOW,(5 sinA - 3 cosA)/(5 sinA + 2 cosA)(4-9/5)/(4+6/5)(11/5)/(26/5)11/26 is the answer

Discussion