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| 1. |
If 3tan 4 equivalent 3 sin theta + 2 cos theta by 3 Sin Theta - 2 cos theta |
| Answer» {tex}3tan\\theta\xa0= 4{/tex}{tex}\\Rightarrow \\tan \\theta = \\frac { 4 } { 3 }{/tex}Given,{tex}= \\frac { 3 \\sin \\theta + 2 \\cos \\theta } { 3 \\sin \\theta - 2 \\cos \\theta }{/tex}{tex}= \\frac { 3 \\tan \\theta + 2 } { 3 \\tan \\theta - 2 }{/tex}[Dividing numerator and denominator by cos\xa0{tex}\\theta{/tex}]{tex}= \\frac { \\left( 3 \\times \\frac { 4 } { 3 } + 2 \\right) } { \\left( 3 \\times \\frac { 4 } { 3 } - 2 \\right) } = \\frac { 6 } { 2 } = 3{/tex} | |