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| 1. |
If√3tanthita=1 then find the value ofsin2thita-cos2thita |
| Answer» Root under 3tanthitha=1Tanthitha=1/root under 3》p=1 & b=rootunder 3》h=root under 4= 2Sin^2thitha-cos^2thitha》(p/h)^2 - (b/h)^2》1/4 - 3/4》- 2/4 = - 1/2 | |