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| 1. |
If 3x=cosec A and 3/x=cot A then find 3( x square minus 1 by x square) |
| Answer» 3x=cosecAX=cosecA/3 ----13/x=cotA3=cotA×X3/cotA=X---------23(x^2-1/x^2)=3((cosecA/3)^2-(1/3/cot)^2)---(from1&2)=3(cosec^2/9-1/9/cotA^2)=3(cosec^2/9-cot^2/9)=3(cosec^2-cot^2/9)=3(1/9);--(cosec^2-cot^2=1) =3×1/9=1/3 answer..Agar clear naa hua to jase ye step likhe h copy per karke dekho samajh aa jayenge ??? | |