1.

If ?4/5,a,2 are three consecutive terms of an ap then find the value of a.

Answer» given 4/5 , a , 2 are in AP=> d = a - 4/5 = 2 - a=> 5a - 4 = 10 - 5a=> 10a = 14=> a = 7/5\xa0


Discussion

No Comment Found