1.

If 4tan theta = 3 evaluate (4sin theta-cos theta+1÷4sin theta +cos theta -1)

Answer» LET x=thetatanx=3/4sec2 x=(1+tan2x)=(1+9/16)=25/16sec x=5/4 ,cos x =4/5sin2x=(1-16/25)=9/25 so sinx=3/5Now (4sinx -cos x+1)/(4sinx+cosx-1)=(4*3/5-4/5+1)/(4*3/5+4/5-1)=(12/5-4/5+5/5)/(12/5+4/5-5/5)=(12-4+5)/12+4-5)=13/11\xa0
The ans is 13/21


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