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| 1. |
If 5x=secΦ and 5/x=tanΦ find the value of 5(x2-1/x2) |
| Answer» sec^2 theta - tan^2 theta =1(5x)^2 - (5/x)^2 =125x^2 - 25/x =1 25( x^2- 1/x^2)=15*5 ( x^2- 1/x^2)=15 ( x^2- 1/x^2)=1/5Answer :-1/5....? | |