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If 8 men and 9 women can do a piece of work in 8 days while 26 men and 48 women can do the same in 2 days, the time taken by 15 men and 10 women in doing the same type of work will be:1). 3 days2). 4 days3). 5 days4). 6 days |
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Answer» If m1MEN and w1woman working together can do a piece of work in d1 days, and m2men and w2 women working together can do it in d2 days men are p times efficient than women then ⇒ d1/d2 = (pm2 + w2)/(pm1 + w1) ⇒ 8/2 = (26P + 48)/(8p + 9) ⇒ 32p + 36 = 26p + 48 ⇒ 6p = 12 ⇒ P = 2 ∴ Time taken by 15 men and 10 women in doing it will be = 8 × {[(2 × 8) + 9]/[(2 × 15) + 10)]} = 5 days |
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