1.

If 9th term of an A.P. is zero,prove that its 29th term is double the 19th term.

Answer» Here,9 the term is 0 so,a+8d=0a= -8d ---(1)Now,A.T.Q,29th term =2(19th term)a+28d=2(a+18d)Putting a= -8d from (1)-8d+28d=2(-8d+18d)20d=2(10d)20d=20dHence proved!!!!!!!!
a9=a+8da=-8da19=a+18d=-8d+18d=10da29=a+28d=-8d+28d=20d


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