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if 9th term of AP is zero ,prove that it\'s 29th term is double of its 19th term.

Answer» a9=a+8d=0 ............. ia29=a+28d..................iia19=a+18d..................iiifrom i and iia= - 8da29= - 8d + 28d a29 = 20d ..... ivfrom i and iiia19 = - 8d + 18d = 10d ... vthus a29 is double of a19 (20d is double of 10d) ...... proved
a9=0a + 8d = 0a= -8d ............... (I)Now, a29 = a + 28d = -8d + 28d = 20dAgain, a19= a + 18 d = -8d + 18d =10dHence, 29th term is double of its 19th term.


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