InterviewSolution
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InterviewSolution
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If `a >0`and discriminant of `a x^2+2b x+c`is negative, then `=a b a x+bb c b x+c a x+bb x+c0`is`+v e`b. `(a c-b)^2(a x^2+2b x+c)`c. `-v e`d. `0`A. `+ve`B. `(ac-b)^(2))(ax^(2)+2bx+c)`C. `-ve`D. `0` |
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Answer» Correct Answer - C here `a gt 0 " and " 4b^(2) -4ac lt 0 , i.e., ac -b^(2) gt 0` `:. .ax^(2) +2bx +c gt 0 ,AA x in R ` Now `Delta = |{:(a,,b,,ax+b),(b,,c,,bx+c),(0,,0,,-(ax^(2)+2bx+c)):}|` `"[Operating " R_(3) to R_(3) -xR_(1)-R_(2)"]"` `=-(ax^(2)+2bx+c)(ac-b^(2))` ` =- (+ve) (+ve) =-ve` |
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