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If `a != 0, b!= 0, c!= 0`, then `|(1 +a,1,1),(1,1 +b,1),(1,1,1 +c)|` is equal toA. abcB. `abc (1 + (1)/(a) + (1)/(b) + (1)/(c))`C. 0D. `1 + (1)/(a) + (1)/(b) + (1)/(c)` |
Answer» Correct Answer - B | |