If A(1,2),B(-3,2)and C(3,-2) be the vertices of the triangle ABC, show that tanA=2.

If A(1,2),B(-3,2)and C(3,-2) be the vertices of the triangle ABC, show

1.	If A(1,2),B(-3,2)and C(3,-2) be the vertices of the triangle ABC, show that tanA=2.
Answer» The vertices of the triangle ΔABC are A (1, 2), B (- 3, 2) and C (3, - 2). The sides of the triangle are AB, BC, CA and we have to find the tangent ratio of the angle A.The slope of the line AB ism₁ = (2 - 2) / (- 3 - 1)= 0 andthat of the line CA ism₂ = (2 + 2) / (1 - 3)= - 2Then the angle A is determined fromtanA = (m₁ - m₂) / (1 + m₁m₂)= (0 + 2) / (1 + 0)= 2Hence tanA = 2