InterviewSolution
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InterviewSolution
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If `|a^2+lambda^2a b+clambdac a-blambdaa b-clambdab^2+lambda^2b c+a c a+blambdab c-alambdac^2+lambda^2||lambdac-b-clambdaa b-alambda|=(1+a^2+b^2+c^2)^3`, then he value of `lambda`is`8`b. `27`c. `1`d. `-1`A. 8B. 27C. 1D. -1 |
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Answer» Correct Answer - C We obserive that the elements in the pre -factor are the cofactors of the corresponding elements of the post factor .Hence `|{:(lambda,,c,,-b),(-c,,lambda,,a),(b,,-a,,lambda):}|= [lambda (lambda^(2) +a^(2)+b^(2)+c^(2))]^(3) =(1+a^(2)+b^(2)+c^(2))^(3)` `rArr lambda=1` Alternate solution: Writing `a=0, b=0c c=0` on both sides we get `lambda^(6)lambda^(3) =1" or " lambda=1` |
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