If a(3,y) is equidistant from p (8,-3) q (7, 6) find the value of y

1.	If a(3,y) is equidistant from p (8,-3) q (7, 6) find the value of y
Answer» pa=qa pa= √ (8-3)²+(-3-y)²= qa =√(7-3)²+(6-y)² √25+y² +6y+9=√16+y²+12y+3634+y²+6y = 52 +y² +12y 6y = -18y = -18/6 = -3 Hence y=-3

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