If A(-3,5),B(-2,-7),C(1,-8)andD(6,3) are the vetice of a quadrilateral abcd find it\'s area

If A(-3,5),B(-2,-7),C(1,-8)andD(6,3) are the vetice of a quadrilateral

1.	If A(-3,5),B(-2,-7),C(1,-8)andD(6,3) are the vetice of a quadrilateral abcd find it\'s area
Answer» It is clear from figure, thatArea of quadrilateral ABCD= Area of\xa0{tex}\\Delta{/tex}ACB + Area of\xa0{tex}\\Delta{/tex}ACD= {tex}\\frac{1}{2}{/tex}[-3( -8 - 7 ) + 1(7 - 5 ) + (-2)(5 - (-8)) ]+ {tex}\\frac{1}{2}{/tex}[-3( -8 - 3 ) + 1(3 - 5) + 6(5 - (-8)) ]= {tex}\\frac{1}{2}{/tex}\xa0[ 45 + 2 - 26 ] + {tex}\\frac{1}{2}{/tex}\xa0[ 33 - 2 + 78 \|=\xa0{tex}\\frac {1} {2}{/tex}\xa0[ 21 + 109 ] = 65 units.