If A(-5,7), B(-4,-5), C(-1,-6) and D(4,5) are the vertices of\xa0⊡ABCD. Find its area.

If A(-5,7), B(-4,-5), C(-1,-6) and D(4,5) are the vertices of\xa0⊡AB

1.	If A(-5,7), B(-4,-5), C(-1,-6) and D(4,5) are the vertices of\xa0⊡ABCD. Find its area.
Answer» by joining B to D,you will get two Triangles ABD and BCD the area of triangle A b d1/2[-5(-5-5)+(-4)(5-7)+4(7+5)]=01[50+8+48]0×2=106/2=53square.unitsalso the area of triangle BCD=1/2[-4(-6-5)-1(5+5)+4(-5+6)]=1/2[44-10+4]=19 square.unitsarea of triangle ABC + area of triangle BCDso the area of quadrilateral ABCD =53+19=72square.units